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DerKrebs [107]
2 years ago
5

Ellus If f(x) = x2, and g(x) = x - 1, then f(g(x)) = [ ? ]x2 +[ ]x+]

Mathematics
1 answer:
Nostrana [21]2 years ago
8 0

Answer:

x^2-2x+1

Step-by-step explanation:

f(x)=x^2

g(x)=x-1

f(g(x))=f(x-1)=(x-1)^2=x^2-2x+1

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stepladder [879]

Answer: B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Ms. Wilson invested ​$34000 in two​ accounts, one yielding 8​% interest and the other yielding 9​%. If she received a total of​
Digiron [165]

Answer:

Amount invested at 8 % rate = x = $ 15000

Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000

Step-by-step explanation:

Total Amount = $ 34000

Let amount invested at 8 % rate = x

Amount invested at 9 % rate = $ 34000 - x

Total interest = $ 2910

2910 = \frac{x (8) (1)}{100} + \frac{(34000-x) (9) (1)}{100}

291000 = 8 x + 306000 - 9 x

x = 306000 - 291000

x = 15000

So  amount invested at 8 % rate = x = $ 15000

Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000

3 0
3 years ago
What is factorisation ​
liubo4ka [24]

Factorization is a method of writing numbers as the product of their factors or divisors.

<em><u>Solution:</u></em>

<em><u>Factorisation:</u></em>

Factorization is a method of writing numbers as the product of their factors or divisors.

In other words we can say, Finding what to multiply together to get an expression.

It is like "splitting" an expression into a multiplication of simpler expressions.

<em><u>Methods of factorisation:</u></em>

  • Factoring out the GCF
  • The sum-product pattern
  • The grouping method
  • The perfect square trinomial pattern
  • The difference of squares pattern

<em><u>Factoring out the GCF:</u></em>

This methods means that factoring out common factors

For example:

12x^2 + 3x = 3x(4x + 1)

This can be used when each term in given expression shares a common factor

<em><u>The sum-product pattern</u></em>

A quadratic equation may be expressed as a product of two binomials

For example:

x^2 + 7x + 12 = (x + 3)(x + 4)

This method can be used for quadratic equations of form ax^2 + bx + c = 0

<em><u>The grouping method</u></em>

If the polynomial is of the form  ax^2 + bx + c and there are factors of ac that add up to b , we can use this method

For example:

2x^2 + 7x + 3\\\\2x^2 + 6x + 1x + 3\\\\2x(x + 3) + 1(x + 3)\\\\(x + 3)(2x + 1)

<em><u>The perfect square trinomial pattern</u></em>

If the first and last terms are perfect squares and the middle term is twice the product of their square roots , we can use this method

For example:

x^2 + 10x + 25\\\\(x + 5)^2

<em><u>The difference of squares pattern</u></em>

If the expression represents a difference of squares, we can use this method

Because a^2 - b^2 = (a + b)(a - b)

For example:

x^2 - 25\\\\x^2 - 5^2\\\\(x + 5)(x - 5)

6 0
3 years ago
5x + y = 6 5x + 3y = -4 The y-coordinate of the solution to the system shown is ___.
8_murik_8 [283]
Subtract these 2 equations,

5x-5x +3y-y = -4-6

2y = -10

y = -5

-5 is your answer.
6 0
3 years ago
Fill in the space to complete to equality:<br><br> 3v-v²=v(__)
levacccp [35]

Answer:

3v-v² = v(3-v)

Step-by-step explanation:

Use distributive property on the right side of the equality.

6 0
3 years ago
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