Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
(2,5) , (6,8)
Distance formula :
d = √(x₂-x₁)² + (y₂-y₁)²
Simply plug in the values.
d = √(6 - 2)² + (8 - 5)²
Simplify.
d = √(4)² + (3)²
Simplify.
d = √16 + 9
Simplify.
d = √25
So, the distance is 5
~Hope I helped!~
Answer:
Step-by-step explanation:
make y=0
0=-2x+3 (Switch the 3 sides)
-3=-2x (Divide everything by -2, cant have a negative x)
2/3=x or 0.66=x
Answer:this is the explanation of the question you have to put what they are asking you too
Step-by-step explanation: