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Masja [62]
3 years ago
14

if a man with type ab blood marries a woman heterozygous for type A what is the probability that their child would be type B???

Biology
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

1/4.

Explanation:

Via a punett square, the only possible combinations are AA, AB, AO and BO. Since BO is the only way the child has type B, the chances are 1 in 4.

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<em>Another way, albeit less accurate, is to count the big squares between R-R intervals and instead of dividing it by 1500, you divide it by 300.</em>

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Greetings!

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~Lauv
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