Answer:
Transitive property
Step-by-step explanation:
When a=c and b=c, a=b
A would be 16+43
B would be 59
C would be 10+49
Answer: 15 students
Step-by-step explanation:
From the question, we are informed that there are 150 students in 6th grade, and that 10% earned straight As last quarter.
The number of students that earned straight As will be:
= 10% × 150
= 10/100 × 150
= 0.1 × 150
= 15 students
11 liters of 25% orange juice, 4 liters of 10% orange juice:
1' let x to be 25% orange juice and y be 10% orange juice
2' .25x+.10y=(15).21
3' x+y=15
4' 2.5x+y=31.5 divide all sides by 10
5' -x-y=-15 multiply all sides by -1
6' 1.5x=16.5
7' x=11
8' y=15-11=4
so 11 and 4 are the answers.
The reciprocal of 6/5 is D. 5/6
Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.
We need to get reciprocal of a fraction when division is performed.
For example: 2 ÷ 1/5
2 may be a whole number but in fraction form it is 2/1.
1st fraction = 2/1
2nd fraction = 1/5
In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.
1/5 ⇒ 5/1
Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10
So, 2 ÷ 1/5 = 10
Answer:
The correct option is (A).
Step-by-step explanation:
The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:
Here,
AGE = age counted in years
PA = appropriate physical activity factor
WT = weight in kilograms
HT = height in meters
The physical activity factor for men and women is:
Activity Level PA (men) PA (Women)
Sedentary 1.00 1.00
Low 1.11 1.12
Active 1.25 1.27
Very Active 1.48 1.45
Given:
AGE = 22 year-old male college student
PA = low = 1.11
WT = 180 pounds = 81.6466 kg
HT = 5'10" = 1.778 m
Compute the value of EER as follows:
Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.
The correct option is (A).
