Answer:
Step-by-step explanation:
Because CB = 6 cm, we can find CD
Use Triangle CDB.
<BCD = <BCA - <ACD
<BCD = ?
<BCA = 90
<ACD = 60
<BCD = 90 - 60
<BCD = 30
Cos 30 = CD / CB
CD = Cos(30) * BC
CD = 5.196 cm
<A = 90 - ACD
<ACD = 60
<A = 90 - 60
<A = 30
Sin(<A) = CB / AB
AB = CB / sin(<A)
AB = 6 / 0.5
AB = 12
Area =1/2 CD * AB
Area = 1/2 * 5.196 * 12
Area = 31.18
Answer:
502 m²
Step-by-step explanation:
We require to find b before calculating the surface area.
The volume (V) of a cuboid is calculated as
V = lbh ( l is length, b is breadth and h is height )
Here V = 510, l = b, b = 10 and h = 3, thus
b × 10 × 3 = 510
30b = 510 ( divide both sides by 30 )
b = 17
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The opposite faces of a cuboid are congruent, thus
top/bottom area = 2(17 × 10) = 2 × 170 = 340 m²
front/back area = 2(17 × 3) = 2 × 51 = 102 m²
sides area = 2(10 × 3) = 2 × 30 = 60 m²
Surface area = 340 + 102 + 60 = 502 m²
