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2 years ago

The picture is there

Mathematics

1 answer:

aliina [53]2 years ago

4 0

Answer:

Step-by-step explanation:

Because CB = 6 cm, we can find CD

Use Triangle CDB.

<BCD = <BCA - <ACD

<BCD = ?

<BCA = 90

<ACD = 60

<BCD = 90 - 60

<BCD = 30

Cos 30 = CD / CB

CD = Cos(30) * BC

CD = 5.196 cm

<A = 90 - ACD

<ACD = 60

<A = 90 - 60

<A = 30

Sin(<A) = CB / AB

AB = CB / sin(<A)

AB = 6 / 0.5

AB = 12

Area =1/2 CD * AB

Area = 1/2 * 5.196 * 12

Area = 31.18

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URGENT!!!! WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER!!!!!!

Zepler [3.9K]

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2 years ago

Which of the following values of x makes this equation true? (-4x – 3) - (7x - 3) = 22

Katena32 [7]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

(-4x-3)-(7x-3) =22 Equation

Step 2

(-4x-3)-(7x-3) =22 Simplify

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Step 3

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Answer

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3 years ago

What equation could be used to find the area of the stage in square meters ?

Novay_Z [31]

Answer:

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2 years ago

Use the graph to write the explicit rule of the arithmetic sequence.

Igoryamba

Answer:

$f_n=7+\left(-2\right)\left(n-1\right)$

Therefore, option C is true.

Step-by-step explanation:

From the graph, we get the sequence

7, 5, 3, 1, ...

Here,

a₁ = 7 is the first element.

An arithmetic sequence has a constant difference 'd' and is defined by

$f_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$5-7=-2,\:\quad \:3-5=-2,\:\quad \:1-3=-2$

The difference between all the adjacent terms is the same and equal to

$d=-2$

substituting a₁ = 7 and d = -2 in the nth term of the sequence

$f_n=a_1+\left(n-1\right)d$

$f_n=7+\left(-2\right)\left(n-1\right)$

Therefore, option C is true.

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3 years ago

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liubo4ka [24]

The domain of a(x) is all of R. The domain of b is the range where $x-4 \geq 0, hence \ x \geq 4$ . We can calculate the composition boa by changing in the expression for b, every x with a(x). Hence, boa(x)= $\sqrt{(3x+1)-4}$ = $\sqrt{3x-3}$ . Again for a function with a root to be defined, we need that the expression under the square root has to be positive. Hence, 3x-3 $\geq$ 0.Thus, the set where this holds is $3x \geq 3, x \geq 1$ . This is also the domain of the function boa(x).

8 0

3 years ago

The picture is there​

The picture is there