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LuckyWell [14K]
3 years ago
14

Omg guys I need help with this question I've failed the test like 4 time because of this question and I give up. Can someone ple

ase help me with this?

Mathematics
2 answers:
Natali [406]3 years ago
6 0

Answer:

D. 270

Step-by-step explanation:

With the information given you can work your way around the table to fill in the blanks

300-120=180 Red-footed one-headed

180+200=380 total red-footed

650-380=270 total black-footed (answer)

270-120=150 black-footed two-headed

150+200=350 two-headed

Dima020 [189]3 years ago
4 0

Answer:

270

Step-by-step explanation:

300-120=180,to get one headed red footed

650-300=350, total two headed.

350-200=150, to get two headed black footed.

150+120=270, total black footed mizjigs

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Answer:

0.72\,\,m^3

Step-by-step explanation:

Given:

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4 years ago
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Alona [7]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

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3 years ago
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Four hu
castortr0y [4]

<em>Answer: h = 120 ft;    w = 80 ft </em>

<em></em>

<em>A = 9600 ft^2</em>

<em />

<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>

<em></em>

<em>A = h*w   (eq1)</em>

<em></em>

<em>The total amount of fence used is:</em>

<em></em>

<em>L = 2*h + 2*w + w    (eq2)    (an extra distance w beacuse of the division)</em>

<em></em>

<em>Solving for w:</em>

<em></em>

<em>w = L - 2/3*h = 480 - 2/3*h   (eq3)  Replacing this into the area eq:</em>

<em></em>

<em></em>

<em></em>

<em>We derive this and equal zero to find its maximum:</em>

<em></em>

<em>   Solving for h:</em>

<em></em>

<em>h = 120 ft.  Replacing this into eq3:</em>

<em></em>

<em>w = 80ft</em>

<em></em>

<em>Therefore the maximum area is:</em>

<em></em>

<em>A = 9600 ft^2</em>

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3 years ago
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