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hodyreva [135]
3 years ago
14

1 1/4 as a whole number

Mathematics
1 answer:
monitta3 years ago
3 0
Probably
Like
Or
Because
It’s
Gong
To
Be
A
Decimal 2.75
You might be interested in
Question 1
Solnce55 [7]

The probability to get heads on all three quarters is 1/8.

<u>Step-by-step explanation:</u>

<u>Given data :</u>

  • Leslie has three quarters.
  • Each quarters have 2 sides namely the Head and the Tail.

<u>It can be determined that :</u>

The total number of possible outcomes you can get from the three quarters with two sides = 2³ ⇒ 2×2×2 ⇒ 8 total outcomes.

If she drops all three of the quarters in the same time, there will be a total of 8 different outcomes.

These 8 outcomes include (T,T,T), (H,T,T), (H,H,T), (T,H,H), (T,T,H), (T,H,T), (H,H,T), (H,H,H).

From the above shown different possible outcomes, you need to find the probability that all three quarters will land on  Heads.

Probability(3 heads)= No. of outcomes with 3 heads / Total no.of  outcomes

We know that,

  • The no.of outcomes with 3 heads is only 1.
  • The total no.of outcomes is 8.

⇒ P( 3 heads ) = 1/8

The probability to get heads on all three quarters is 1/8.

3 0
4 years ago
Choose the operation.
qwelly [4]

Answer:

<u>Niagara Falls will have 35,000 years of formation then</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Niagara Falls was formed 10,000 years ago

Scientists predict it will  last for another 25,000 years

2. How old will Niagara Falls be then?

10,000 + 25,000

35,000

<u>Niagara Falls will have 35,000 years of formation then</u>

3 0
3 years ago
Which of the following rational functions is graphed below?
KiRa [710]

Answer: D

Step-by-step explanation:

A p e x

3 0
3 years ago
(5) Blackbeard and Shamus find a treasure chest with $40,000 in coins inside. Blackbeard takes
Korolek [52]

Answer:

Blackbeard

Step-by-step explanation:

set of equation: f(x) = 15,000(1.08)^x

x = years; 15,000(1.08)^5

shamus is about 22039.921152

25000>22039.921152

3 0
3 years ago
Assume that when adults with smartphones are randomly​ selected, 47​% use them in meetings or classes. If 10 adult smartphone us
salantis [7]

Answer:

\approx 0.31

Step-by-step explanation:

This is a typical binomial experiment.

Let's remember what is a binomial experiment:

A binomial experiment is an experiment where you have a fixed number of independent trials with only have two outcomes (that's why is called BInomial). The probability remains constant from trial to trial.

In this case, we have 10 users (fixed number) and the result of each user doesn't affect the result of the other one (they are different people and they take their own decisions). The two outcomes are they use their smartphones in meetings or classes, or not. The probability is always the same, with a 47% of probability they use their smartphones in meetings (in our case, this is called a "success" because is what we are trying to analyze) and with a 100% - 47% = 53% they don't.

With this information, let's define X = number of users that use their smartphones in meetings or classes, X has a binomial distribution with parameters (10,47%) (10 is the total of trials and 47% the probability of success).

Let's remember that the probability of getting exactly k successes in n trials, in a binomial distribution with parameters (n, p), is given by the probability mass function:  

P(k) = \binom{n}{k} * p^k * (1-p) ^(n-k)

We want the probability that at least 6 of them use their smartphones, that means that we need 6, 7, 8, 9 or 10 users use them

P(X\geq 6) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)

Now we just use the probability mass function, with n=10 and p=47/100 = 0.47, for each k ⊆ {6, 7, 8, 9, 10}:

\binom{10}{6} * 0.47^6 * (1-0.47)^(10-6) + \binom{10}{7} * 0.47^7 * (1-0.47)^(10-7) + \binom{10}{8} * 0.47^8 * (1-0.47)^(10-8) + \binom{10}{9} * 0.47^9 * (1-0.47)^(10-9) + \binom{10}{10} * 0.47^(10) * (1-0.47)^(10-10) =\\ \\ \frac {10!} {6!4!} * 0.47^6 * 0.53^4 + \frac {10!} {7!3!} * 0.47^7 * 0.53^3 + \frac {10!} {8!2!} * 0.47^8 * 0.53^2 + \frac {10!} {9!1!} * 0.47^9 * 0.53^1 + \frac {10!} {10!0!} * 0.47^(10) * 0.53^0

Now we just do the calculation and we get

P(X\geq 6) \approx 0.31

3 0
3 years ago
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