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3 years ago

1 1/4 as a whole number

Mathematics

1 answer:

monitta3 years ago

3 0

Probably
Like
Or
Because
It’s
Gong
To
Be
A
Decimal 2.75

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A student says that if 5x2 = 20, then x must be

lutik1710 [3]

Answer:

I agree with the student's answer. "x" cannot be -2 because then it would make -20 which is not equal to 20:

5(-2)(2) = ?

-10 x 2 = ?

? = -20

-20 ≠ 20

Step-by-step explanation:

Justificaiton:

5(x)(2) = 20

10(x) = 20

10/10(x) = 20/10

x = 2

Second Justification:

5(x)(2) = 20

5/5(x)(2) = 20/5

2x = 4

2x/2 = 4/2

x = 2

4 0

3 years ago

Factorise each of the following algebraic expressions completely,

LekaFEV [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

2k - 6k² + 4k³ ← factor out 2k from each term

= 2k(1 - 3k + 2k²)

To factor the quadratic

Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

The factors are - 1 and - 2

Use these factors to split the k- term

1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )

1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term

= (1 - k)(1 - 2k)

1 - 3k + 2k² = (1 - k)(1 - 2k) and

2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)

(b)

Given

2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )

= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

= (x - 2y)(2a + 3b)

8 0

3 years ago

Urgent!

Kamila [148]

Answer:

The mode is 75

Step-by-step explanation: It is the one that appears most often

5 0

3 years ago

The princess examines one plant and can’t seem to locate its roots. The plant is labeled as p(x)=x^2+x+3 Which values should the

AleksAgata [21]

Let's actually find the roots, using the quadratic formula:

<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.

-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2

The discriminant here is negative, so the roots x will be complex:

-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2

These are irrational roots; they cannot be expressed as the ratios of integers.</span>

8 0

3 years ago

Sylvie folds a large piece of paper in half. The fold divides the paper into two equal parts. She folds it in half again. When s

Nikolay [14]

Each time you fold a paper it will double the amount of parts. When you think about it, it's just multiplying by 2 a bunch of times.

One fold is 2 times 1, which is 2.
The second fold is 2 times 2, which is 4.
The third fold is 4 times 2, which is 8.

Using this process, we can simplify that into exponents. If the amount of times you fold is x and the parts double for each fold, then the amount of parts can be represented by:

$2^{x}$

So if the amount of parts is given and we need the amount of folds, just keep doubling until you get to 64. The amount of times you doubled is the number of times Sylvie folded.

Later you will learn that the opposite of an exponent is a logarithm, which would look like this:

$log_{2}(64) = ?$

But don't worry about that yet.

6 0

3 years ago