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3 years ago

What is 9(x + 8) + x(5+4)

Mathematics

2 answers:

lina2011 [118]3 years ago

7 0

Answer:

72+ 18x

Step-by-step explanation:

9x+72+5x+4x

72+ 18x

Softa [21]3 years ago

7 0

9(x + 8) + x(5 + 4)

9x + 72 + 5x + 4x

18x + 72

(If you have been asked to solve for x then also include the following, if not then only write what is above!)

18x + 72 = 0

18x = -72

x = -4

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Sandra is making decorations for the school dance out of construction paper. Each decoration uses 223 2 2 3 sheets of paper. San

scoundrel [369]

Answer:

Step-by-step explanation:

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7 0

3 years ago

(help) Miller’s Farm had apples on sale for $1.78 a pound. Maria spent $15.21 on apples. How many pounds did she buy?

jolli1 [7]

Answer:

8.5 pounds

Step-by-step explanation:

$ 1.78 - 1 pound

$ 15.21 - 15.21/1.78

= 8.5

5 0

2 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

Ann and Tom want to establish a fund for their grandson's college education. What lump sum must they deposit at an 8.2% annual

GaryK [48]

Compound interest formula = a=P(1+r/n)^nt

P= lump sum to deposit (solving for)

A= amount accumulated over the entire time (20000)

n= number of times interest is compounded annually (1)

r= rate of interest (0.82)

T= total number of years (15)

20000=P(1+0.082/1)^1*15

20000=P(1.082)^15
20000=P(3.26143638)
20000/3.26143638=P
P=$6132.2674

7 0

3 years ago

Read 2 more answers

-8)(56)=1<br><br> What is the missing value that makes the equation true?

Rudik [331]

the correct answer is -448

7 0

3 years ago