X = 10
X+4/2=7
multiply both sides by 2
X+4=14
subtract 4 from both sides
x=10
Answer:
x = 17
∠A = 114°
Step-by-step explanation:
In the figure attached, the complete question is shown.
From the figure, we know that:
∠A = ∠B
Replacing with the expressions, we get:
6x+12 = 3x+63
6x - 3x = 63 - 12
3x = 51
x = 51/3
x = 17
∠A = 6(17)+12
∠A = 114°
<h3>Answer:</h3>
B) 10 pounds
<h3>Explanation:</h3>
Let x represent the amount of 70¢ candy to be added. The value of the mixture can be written as ...
... 90×30 + 70x = 85×(30+x) . . . . . where 30+x is the total weight of the mix
... 2700 +70x = 2550 +85x
... 150 = 15x . . . . . . add -70x-2550
... 10 = x . . . . . . . . . divide by the coefficient of x
10 pounds of candy at 70¢/lb must be added.
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
There is no question? ...
