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zavuch27 [327]
3 years ago
10

Which of the following series are convergent?

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer:

All of them

Step-by-step explanation:

According to the ratio test, for a series ∑aₙ:

If lim(n→∞) |aₙ₊₁ / aₙ| < 1, then ∑aₙ converges.

If lim(n→∞) |aₙ₊₁ / aₙ| > 1, then ∑aₙ diverges.

(I) aₙ = 10 / n!

lim(n→∞) |(10 / (n+1)!) / (10 / n!)|

lim(n→∞) |(10 / (n+1)!) × (n! / 10)|

lim(n→∞) |n! / (n+1)!|

lim(n→∞) |1 / (n+1)|

0 < 1

This series converges.

(II) aₙ = n / 2ⁿ

lim(n→∞) |((n+1) / 2ⁿ⁺¹) / (n / 2ⁿ)|

lim(n→∞) |((n+1) / 2ⁿ⁺¹) × (2ⁿ / n)|

lim(n→∞) |(n+1) / (2n)|

1/2 < 1

This series converges.

(III) aₙ = 1 / (2n)!

lim(n→∞) |(1 / (2(n+1))!) / (1 / (2n)!)|

lim(n→∞) |(1 / (2n+2)!) × (2n)! / 1|

lim(n→∞) |(2n)! / (2n+2)!|

lim(n→∞) |1 / ((2n+2)(2n+1))|

0 < 1

This series converges.

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5.47 inches of rain

Hope this helps!
7 0
3 years ago
Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.
kupik [55]

Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

5 0
3 years ago
Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below:
igomit [66]
B. 0

G(6)= 6 - 8 = -2

F(-2) = 6(-2) + 12 = 0
6 0
4 years ago
N a school trip, students stopped for breakfast. They chose between a bagel and a ham biscuit.
svetlana [45]
<h2><u><em>GLAD YOU FOUND YOUR ANSWER!!!!!!</em></u></h2>

4 0
3 years ago
I WILL GIVE BRAINLIEST HELP PLEASEEEE HELP PLEASEEE
Lady bird [3.3K]

Answer:

-39

Step-by-step explanation:

\left(-3\right)^3-\sqrt[3]{27}-4^3\left(\sqrt[3]{64}-\left(2\right)\left(2\right)\right)-\frac{\left(3\right)^3\left(2\right)}{6}

-27-3-64\left(4-4\right)-\frac{54}{6}

-27-3-\frac{54}{6}

-27-3-9

Which gives us -39.

5 0
3 years ago
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