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3 years ago

Find the measure of 6

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

4 0

101 because 180-79=101

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5-x<8;x=-3 how do you solve that?

Sergio [31]

Make sure you substitute x for 3

The equation would be:

5-3<8

Subtract 3

2<8

The statement is true

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=6%20%5Cdiv%20131.4" id="TexFormula1" title="6 \div 131.4" alt="6 \div 131.4" align="absmiddle"

Svetradugi [14.3K]

Answer: 21.9

131.4 divided by 6

4 0

3 years ago

-24 = -3w +21 what is w?

yuradex [85]

Answer:

w=15

Step-by-step explanation:

7 0

3 years ago

Which expression is equivalent to the expression shown?

choli [55]

<h3>Answer: 5^24</h3>

<h2>Maybe it can be your answer but i am not sure that it is fixed answer </h2>

5 0

3 years ago

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

3 years ago