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mr_godi [17]
3 years ago
6

5-x<8;x=-3 how do you solve that?

Mathematics
1 answer:
Sergio [31]3 years ago
8 0
Make sure you substitute x for 3

The equation would be:

5-3<8

Subtract 3

2<8

The statement is true
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Solve the equality 2(4x+1 )&lt; 3(2x-3)
Musya8 [376]

Answer:

Step-by-step explanation:

2(4x+1)<3(2x-3)

simplify to

8x+2<6x-9

we can add 9 to both sides and subtract 8x from both sides

11<-2x

divide by -2

-5.5>x

7 0
2 years ago
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8 0
3 years ago
8(s+3)=72 i need help it is due tomorrow
Montano1993 [528]

Answer:

s = 6

Step-by-step explanation:

8(s+3) = 72

Expand the brackets out:

(8 x s) + (8 x 3) = 72

8s + 24 = 72

Now you get rid of 24 on the left, by taking away 24. But you also have to do the same on the right side so that both sides are equal:

8s + 24 = 72

left(-24) = right (-24)

So that leaves you with:

8s = 48

Now divide both sides by 8 to make them equal and to get s on its own:

8s = 72

left(/8) = right (/8)

Therfore:

s = 6


3 0
3 years ago
Simplify: 35z4 + 11z4.
nydimaria [60]
35z^4 + 11z^4<span>
= 46z^4 ...combine like terms

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4 0
2 years ago
Read 2 more answers
Write 2/3 of 4 as a fraction
eduard
 2 / 3 of 4 = ( 2 x 4 ) / 3 = 8 / 3 ;
7 0
3 years ago
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