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ololo11 [35]
3 years ago
15

Find the area of the figure. Round to the nearest tenth if necessary.

Mathematics
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

63 sq ft

Step-by-step explanation:

The formula for the area of a trapezoid is

A = h(a + b)/2  where a and b are the lengths of the parallel sides and h is the distance between them

A = 7(11 + 7)/2

   = 7(18)/2

   =  63 sq ft

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A coin is tossed and an eight​-sided die numbered 1 through 8 is rolled. Find the probability of tossing a tail and then rolling
andreyandreev [35.5K]

Answer:

5/16

Step-by-step explanation:

P(tails) = 1/2

P(>3) = 5/8

P(tails AND >3) = 1/2 × 5/8 = 5/16

3 0
3 years ago
How do I find the equation of the perpendicular bisector between (-2,5) and (2,-1)?
Arturiano [62]

Answer:

y =  \frac{2}{3} x + 2

Step-by-step explanation:

Start by finding the slope of the given line.

\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }

Slope of given line

=  \frac{5 - ( - 1)}{ - 2 - 2}

=  \frac{5 + 1}{ - 4}

=  \frac{6}{ - 4}

=  -  \frac{3}{2}

A perpendicular bisector cuts through the line at its midpoint perpendicularly.

The product of the slopes of two perpendicular lines is -1.

Let the slope of the perpendicular bisector be m.

-  \frac{3}{2} m =  - 1

m =  - 1 \div ( -  \frac{3}{2} )

m =  - 1 \times ( -  \frac{2}{3} )

m =  \frac{2}{3}

y =  \frac{2}{3}x  + c, where c is the y-intercept.

To find the value of c, we need to substitute a pair of coordinates that lies on the perpendicular bisector into the equation. Since the perpendicular bisector passes through the midpoint of the given line, we can use the midpoint formula to find the coordinates.

\boxed{midpoint = ( \frac{x _{1} + x _2}{2} , \frac{y_1  + y_2}{2} )}

Midpoint of given line

=  ( \frac{ - 2+ 2}{2} , \frac{5 - 1}{2} )

=( \frac{0}{2} , \frac{4}{2} )

= (0, 2)

y =  \frac{2}{3} x + c

When x= 0, y= 2,

2= ⅔(0) +c

2= 0 +c

c= 2

Thus, the equation of the perpendicular bisector is y =  \frac{2}{3} x + 2.

7 0
3 years ago
What is the expected frequency of east campus and passed?
ser-zykov [4K]

The expected frequency of east campus and passed is C. 42 students

<h3>How to calculate the value?</h3>

The table for expected frequency is ,

East Campus West Campus Total

Passed (84*100)/22=42 (84*100)/200 =42 84

Failed (116*100)/200=58 (116*100)/22=58 116

Total 100 100 200

Passed = 84×100/200

= 42

Therefore, the expected frequency of East Campus and Passed is 42 students.

Learn more about frequency on:

brainly.com/question/254161

#SPJ4

3 0
1 year ago
write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
3 years ago
Classify the product as a whole number
ch4aika [34]
Let's solve for the answer to determine if it is rational.  

\frac{-2 \frac{2}{5} }{-4}=12/5/4= \frac{3}{5} &#10;&#10;&#10; it is a rational number.
4 0
3 years ago
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