Can someone help me I don't know how to do it?Please and thank u Expand - 2 (1 - 2x + 2)
2 answers:
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Answer:- AAS postulate
Explanation:-
- AAS postulate tells that if two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.
Given:- One angle and one side of a triangle is equal to the one angle and one side of the other triangle.
We see there is one more pair of equal angles as they are vertically opposite angles . [See the attachment]
⇒ there is a triangle where two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.
⇒ The triangles are congruent [ by ASA postulate]
Answer:
2 and -
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
3y = 6x + 9 ( divide all terms by 3 )
y = 2x + 3 ← in slope- intercept form
with slope m = 2
(i)
Parallel lines have equal slopes, thus
the slope of line t is 2
(ii)
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
, thus
the slope of line r is -
The number of permutations of picking 4 pens from the box is 30.
There are six different unique colored pens in a box.
We have to select four pens from the different unique colored pens.
We have to find in how many different orders the four pens can be selected.
<h3>What is a permutation?</h3>A permutation is the number of different arrangements of a set of items in a particular definite order.
The formula used for permutation of n items for r selection is:
Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1
We have,
Number of colored pens = 6
n = 6.
Number of pens to be selected = 4
r = 4
Applying the permutation formula.
We get,
=
= 6! / 4!
=(6x5x4x3x2x1 ) / ( 4x3x2x1)
= 6x5
=30
Thus the number of permutations of picking 4 pens from a total of 6 unique colored pens in the box is 30.
Learn more about permutation here:
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