Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Hello and Good Morning/Afternoon
<u>Let's tale this problem step-by-step</u>:
<u>What does the problem want:</u>

<u>Employment compensation</u> =55% of the average of the last 26-week salary

⇒ 55% of that average

<u>Answer: $400.65</u>
Hope that helps!
#LearnwithBrainly
Ron must work 9 hours. If he makes 300 every 5 hours, that means he makes 60 every hour. 60x9 = 540
Answer: 8 is the slope
Step-by-step explanation:
Y-7=8(x-14)
Y-7= 8x-112
Y= 8x -105
Work is provided in the image attached.
Although you did not include units, I just used centimeters.
However, if there were no units, then just put your answer.
If you do not understand my work,
please ask me in the comments below.