To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
Answer:
(f o g)(-2)= 11
Step-by-step explanation:
Answer:
x = 1.2
y = 6.6
Step-by-step explanation:
1) y= -2x+9
2) 8x-3=y
Substitute y in equation 1 using y in equation 2.
8x - 3 = -2x + 9
+ 3 on both sides
8x = -2x + 12
+ 2x on both sides
10x = 12
x = 1.2
To find y, plug in x
8x - 3 = y
9.6 - 3 = y
6.6 = y
Hope this helps :)
You basically add 17.50+17.50=35 and add 35+35=70, reason being is because the 35 is the 1/2 and 17.50 is the 1/4 so 70 is your answer