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3 years ago

Find three consecutive even integers if three times the first integer is two times the third.

Mathematics

2 answers:

drek231 [11]3 years ago

6 0

Using a system of equations, it is found that the three consecutive even integers are -8, -6 and -4.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the three consecutive even integers are represented by:

n, n + 2, n + 4

The first integer is two times the third, hence:

n = 2(n + 4)

2n + 8 = n

n = -8

Thus:

n = -8

n + 2 = -8 + 2 = -6

n + 4 = -8 + 4 = -4

The integers are -8, -6 and -4.

To learn more about system of equations, you can take a look at brainly.com/question/26650649

iren [92.7K]3 years ago

5 0

Answer:

8,10,12

Step-by-step explanation:

Step-by-step explanation:

Smallest Integer = 2x - 2

Middle integer = 2x

Largest integer = 2x + 2

All three are every

3(2x - 2) = 2(2x + 2)

6x - 6 = 4x + 4 Add 6 to both sides

6x = 4x + 6 + 4 Combine

6x = 4x + 10 Subtract 4x from both sides

6x-4x = 10 Combine

2x = 10 Divide by 2

x = 10/2

x = 5

2x - 2 = 2*5 - 2 = 8

2x = 10

2x+2 12

3*8 = 2*12

24 = 24

So the answers are correct.

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2 years ago

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3 years ago

Find three consecutive even integers if three times the first integer is two times the third.​

Find three consecutive even integers if three times the first integer is two times the third.