For left put 2 on each
On the box over 100 put 82, and put 82 in the box on the right
Well you would have to round this 5 and above goes up. Since 1 is lower than 5 that would leave you at 6.37. 7 rounds up so that would change to 6.4. Lastly 4 would round down, So that would leave you with 6. Now 6 is the simplest form but if your looking for rounded to the nearest tenth the answer would be 6.4. If your looking for rounded to the nearest 100th place 6.37. But over all simplest form is 6.
ANSWER
![-\frac{\sqrt[]{3}}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D)
EXPLANATION
Given

We can find cos 150 by using

recall that
![\begin{gathered} \cos 30=\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%2030%3D%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Hence,
![\begin{gathered} \cos 150=-\cos 30 \\ =-\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20150%3D-%5Ccos%2030%20%5C%5C%20%3D-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Therefore, the value of cos 150 is
![-\frac{\sqrt[]{3}}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D)
Answer:
Length of DE is : 18√2 units
Step-by-step explanation:
The length of a side of a triangle is 36.
To calculate : The length of the segment DE
Now, the two parts of triangle have equal area ∴ Area(ADE) = Area(BDEC)

In ΔABE and ΔABC,
∠A = ∠A (Common angles)
∠ABE = ∠ABC (Corresponding angles are always equal)
By AA postulate of similarity of triangles, ΔABE ~ ΔABC.
Hence by area side proportionality theorem

Hence, length of DE is 18√2 units