Write the coordinates of the vertices after a reflection over the y-axis.
2 answers:
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Answer:
Step-by-step explanation:
<em>Hey there!</em>
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Well to find the solution the the given system,
3y - 2x = -9
y = -2x + 5
So to find x lets plug in -2x + 5 for y in 3y - 2x = -9.
3(-2x + 5) - 2x = -9
Distribute
-6x + 15 - 2x = -9
-8x + 15 = -9
-15 to both sides
-8x = -24
Divide -8 to both sides
<u>x = 3</u>
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Now that we have x which is 3, we can plug in 3 for x in y = -2x + 5.
y = -2(3) + 5
y = -6 + 5
<u>y = -1</u>
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So the solution is (3,-1).
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<em>Hope this helps :)</em>
Answer:
n= -4
Step-by-step explanation:
First we have to find the equation of line which passes through (6,3) and (8,4).
Then we have to pass this line through the point (n , -2).
we know, equation of line passing through (x1,y1) and (x2,y2) is
So, the equation of line passing through (6,3) and (8,4) is
or,
multiplying both sides by -2
x-6=2(y-3)
or, x-6=2y-6
or, x-2y=6-6
or, x-2y=0
Now, we have to pass this line through (n,-2)
So, using the point in the line, that is using x=n , y=-2
we get
n-2(-2)=0
or, n+4=0
or, n=-4