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icang [17]
3 years ago
9

Based on the tables, at what point do the lines y = 3x - 2 and y = -5x - 10 intersect?

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0
Intersect at where x=x and y=y
see where they have the same x and y values
that is at x=-1 and y=-5
intersect at (-1,-5)
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Mark as brainleist if right? HMMMMMMMM<br> FELLING GOOD TODAY
Alekssandra [29.7K]

Answer:

-50

Step-by-step explanation:

Add 2 to both sides: \frac{c}{5} =-12+2=-10

Multiply both sides by 5: c = 5 * (-10) = -50.

Thus, the answer is -50.

Hope this helps!

3 0
4 years ago
Read 2 more answers
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
4 years ago
NEED HELP ASAP PLEASE
Tju [1.3M]

Answer:

9/35

Step-by-step explanation:

no of even number =3(2,4,6)

probablity of getting even in both dice =(3/6)×(3/6)

=9/36

4 0
3 years ago
A game is played using two spinners. Spinner A has four sections labelled 2, 4, 6, 8 and Spinner B has labelled 1, 3, 5. Players
Margarita [4]

Answer:

1500p

Step-by-step explanation:

The spinner A has 4 possible values, and the spinner B has 3 possible values, so the total number of possibilities for both spinners is the product of these number of possibilities:

4 * 3 = 12

From these 12 possible pair of values, the ones that give a sum of 7 are:

(6,1), (4,3) and (2,5).

We have 3 cases where the sum is 7, so the probability of having a sum of 7 is 3/12 = 25%. Therefore, the probability of not having a sum of 7 is 75%

To find the expected value, we multiply the probability of each case by the value it would give. If the player wins, the school loses 10p (the player paid 20p and earned 30p), and if the player loses, the school wins 20p. So the expected value of 120 games is:

120 * (0.25 * (-10) + 0.75 * (20)) = 1500p

6 0
3 years ago
the price of a guiter was decreased by 15% and sold for 275.99. what was the orignal price of the guiter in dollers?
KATRIN_1 [288]

Answer: 317.39

Step-by-step explanation:

The price of the guitar decreased by15%

Original price is 275.99

To get the reduced amount

It will be 15% of the exact amount and add to the exact to get the original

15/100×275.99

=41.3985

To get exact,

reduced amount + sold price

=41.3985+275.99

=317.3885

=317.39

7 0
3 years ago
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