Based on the tables, at what point do the lines y = 3x - 2 and y = -5x

PLEASE HELP I WILL GIVE BRAINLIEST

ale4655 [162]

Answer:

.64 .81 .46 .40 .04 13% 22% 06% 76% 76%

c i argree with both because 80% as a decmial can be both .8 and .80

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the missing pattern 7, 11, 2, 18, -7

Alexxx [7]

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula $n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}$ , equivalent to the <em>recurrence</em> formula $a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}$ .

<h3>What is the missing element in a sequence?</h3>

A sequence is a set of elements which observes at least a <em>defined</em> rule. In this question we see a sequence which follows this rule:

$n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}$ (1)

Now we prove that given expression contains the pattern:

n = 0

7

n = 1

7 + (- 1)² · 2² = 7 + 4 = 11

n = 2

7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2

n = 3

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18

n = 4

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula $n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}$ , equivalent to the <em>recurrence</em> formula $a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}$ .

To learn more on patterns: brainly.com/question/23136125

#SPJ1

8 0

2 years ago

What is each percent of change? Round to the nearest whole percent if

Kipish [7]

Answer:

Its an increase

30 to 90

I= 100 x (f-i)/i

I= 100 x 90-30/30

I= 100 x 2

200% increase

3 0

2 years ago

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

7 0

2 years ago

Pls help!!

AleksAgata [21]

Answer:

11.25

Step-by-step explanation:

15x3/4=45/4=11.25pounds

8 0

3 years ago

Based on the tables, at what point do the lines y = 3x - 2 and y = -5x - 10 intersect?