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2 years ago

Complete the equation of the line through (-8,-2)(-4,6) use exact numbers

Mathematics

1 answer:

Firdavs [7]2 years ago

6 0

Answer:

y = 2x + 14

Step-by-step explanation:

Hope this helps!!!

First, you have to find the slope by using

In other words,

The slope is 2.

Then you plug the rest into point-slope form (you can use either of the points, I used the first one)

Remember that m is the slope.

Distribute the slope to the parenthesis

Isolate the y variable

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Please help me with 1,2,3 and show me how you get it the answers and how you get it do not send me link please I need help someo

elena-s [515]

Answer:

1) 20 cm

2) 22.4 in

3) 15 ft

Step-by-step explanation:

For this question, you have to use the Pythagorean theorem.

Why?

Well, because it is a right triangle and you have 2 sides given and you want to find the third side.

Now let's solve this problem!

For number 1 we have:

a = 16 cm and B = 12 cm

you need to find the 3rd side which is c (aka the hypothenuse)

so let's write the equation:

a^2 + b^2 = c^2

Then we substitute with what we have given.

16^2 + 12^2 = c^2

Using a calculator solve the equation

400 = c^2

Now we have to find the square root from both sides of the equation.

c = 20 cm (That's the final answer)

For number 2 we have:

a = 10 in and b = 20 in

we follow the same steps as in number 1

a^2 + b^2 = c^2

10^2 + 20^2 = c^2

500 = c^2

c = 22.4 in (That's the final answer)

For number 3 we have:

a = 9 ft and b = 12 ft

a^2 + b^2 = c^2

9^2 + 12^2 = c^2

225 = c^2

c = 15 ft (That's the final answer)

8 0

2 years ago

It cost benjamin 1.35 to send 9 text messages. How much would it cost to send 118 text messages?

Hatshy [7]

price of one message = 1.35 ÷ 9

1.35 ÷ 9 = 0.15

0.15 • 118 = ( 3 ÷ 20 ) • 118

118 • 3 = 354

354 ÷ 20 = 177 ÷ 10 = $17.7 to send 118 messages

please give brainliest

6 0

2 years ago

Keller boat travels 24mph. find the rate of the river if she can travel 6 mi upstream. in the same amount of time she can go 10

nikitadnepr [17]

The correct answer is:

6 mph.

Explanation:

We will use the formula d = rt for this, where d is distance, r is rate, and t is time.

We know that the time for both distances is the same; this means we want to isolate t in our formula. To do this, we will cancel r by dividing both sides:
d/r = rt/r
d/r = t

We will write an expression for the time upstream, an expression for the time downstream, and set them equal.

For the time upstream, the distance is 6 and the rate is 24-x; this gives us

$\frac{6}{24-x}$

For the time downstream, the distance is 10 and the rate is 24+x; this gives us

$\frac{10}{24+x}$

Together, these give us the equation

$\frac{6}{24-x}=\frac{10}{24+x}$

We cross-multiply to solve this:
6(24+x) = 10(24-x)

Using the distributive property, we have
6*24 + 6*x = 10*24 - 10*x
144+6x = 240-10x

Adding 10x to each side,
144+6x+10x = 240-10x+10x
144+16x = 240

Subtract 144 from each side:
144+16x-144 = 240-144
16x = 96

Divide both sides by 16:
16x/16 = 96/16
x = 6

4 0

3 years ago

Read 2 more answers

Which describes how to find the solution to 3p < 14? 

Paraphin [41]

Formula
3p < 14
step 1 : 3p / 3 < 14 / 3
; divide 3p, by 3, and 14 by 3
p is about 4.67 ( rounded, original is 4.66666666666666.... etc)

8 0

3 years ago

Read 2 more answers

Solve the logarithmic equation. Show steps

Morgarella [4.7K]

$\begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \underset{\stackrel{\uparrow }{\textit{let's use this one}}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] ~\dotfill$

$\log_4(x+10)-\log_4(x-2)=\log_4(x)\implies \log_4\left( \cfrac{x+10}{x-2} \right)=\log_4(x) \\\\\\ \stackrel{\textit{exponentializing both sides}}{4^{\log_4\left( \frac{x+10}{x-2} \right)}=4^{\log_4(x)}}\implies \cfrac{x+10}{x-2}=x\implies x+10=x^2-2x \\\\\\ 10=x^2-3x\implies 0=x^2-3x-10 \\\\\\ 0=(x-5)(x+2)\implies x= \begin{cases} 5~~\checkmark\\ -2 \end{cases}$

notice, -2 is a valid value for the quadratic, however, the argument value for a logarithm can never 0 or less, it has to be always greater than 0, so for the logarithmic expression with (x-2), using x = -2 will give us a negative value, so -2 is no dice.

4 0

2 years ago