We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
Answer: the answer to this solution is 8.04
Answer:
33
Step-by-step explanation:
6x - 3y
=> x = 5, y = -1 Substitute in the above equation,
=> 6(5) - 3(-1)
=> 6(5) + 3
=> 30 + 3
=> 33
Answer:
12 to the 5th power and is it 248,832
Step-by-step explanation:
8a+3b+8a-4b=
8a+8a+3b-4b=
16a-1b=
16a-b
Hope I didn't mess up for your sake!
