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erma4kov [3.2K]
3 years ago
12

A quantity with an initial value of 390 the keys continuously at a rate of 5% per decade what is the value of the quantity after

51 years to the nearest hundred
Mathematics
1 answer:
Fed [463]3 years ago
3 0

Answer:

4695.90

Step-by-step explanation:

The exponential growth function is given as:

y = a(1 + r)^t

a = Initial value = 390

y = Value after time t = ?

r = Growth rate = 5% = 0.05

t = Time in years =51

Hence

y = 390(1 + 0.05)⁵¹

y = 4695.9002123

Approximately = 4695.90

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C+3c is 4c and -4+9 is 5 so your answer is 4c+5
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Edgar pay $67.86 for 7.8 pounds of fertilizer. What is the price per pound of fertilizer?
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He pays $8.70

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What is the value expression 8+24 divided by (2 times 6) - 4
Sphinxa [80]

Answer:

6

Step-by-step explanation:

Given mixed operations there is a particular order that must be followed.

Using the order set out in the acronym PEMDAS

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2 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

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