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erma4kov [3.2K]
3 years ago
12

A quantity with an initial value of 390 the keys continuously at a rate of 5% per decade what is the value of the quantity after

51 years to the nearest hundred
Mathematics
1 answer:
Fed [463]3 years ago
3 0

Answer:

4695.90

Step-by-step explanation:

The exponential growth function is given as:

y = a(1 + r)^t

a = Initial value = 390

y = Value after time t = ?

r = Growth rate = 5% = 0.05

t = Time in years =51

Hence

y = 390(1 + 0.05)⁵¹

y = 4695.9002123

Approximately = 4695.90

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7 0
4 years ago
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Bryan estimates the cost of a vacation to be $730. The actual cost of the vacation is $850. Find the percent error. Round the ne
Ray Of Light [21]
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8 0
3 years ago
4(х +Зу) = 2(3х-y)<br> Solve for x
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3 years ago
2(x-3)-12 = -4<br> How do I solve this equations
deff fn [24]

Answer:

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Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12    (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

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Algebra Question ( Matrices and Determinants ) 20 point
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6 0
3 years ago
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