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Zigmanuir [339]
3 years ago
12

You scored 53 in fight 1 and 103 in fight 2

Mathematics
1 answer:
sergey [27]3 years ago
5 0
103+53=156
156/2=78
The average or mean is 78
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A service center receives an average of 0.6 customer complaints per hour. Management's goal is to receive fewer than three compl
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Answer:

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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e = 2.71828 is the Euler number

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8 hours means that h = 8, \mu = 0.6(8) = 4.8.

The probability is P(X = 4).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-4.8}*4.8^{4}}{(4)!} = 0.18203

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