Question 5
1 answer:
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Answer:
Probability that at least one of them suffers from arachnophobia is 0.5160.
Step-by-step explanation:
We are given that a 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia).
Also, At a summer camp there are 10 teenagers sleeping in each tent.
Firstly, the binomial probability is given by;
where, n = number of trials(teenagers) taken = 10
r = number of successes = at least one
p = probability of success and success in our question is % of
the teenagers suffering from arachnophobia, i.e. 7%.
Let X = Number of teenagers suffering from arachnophobia
So, X ~
So, probability that at least one of them suffers from arachnophobia
= P(X >= 1) = 1 - probability that none of them suffers from arachnophobia
= 1 - P(X = 0) = 1 -
= 1 - (1 * 1 * ) = 1 - 0.484 = 0.5160 .
Therefore, Probability that at least one of them suffers from arachnophobia is 0.5160 .
Answer:
7 and 13
Step-by-step explanation:
let the 2 numbers be x and y , x > y , then
x = y + 6 → (1)
(x + y) = y - 2 ( multiply both sides by 4 to clear the fraction )
x + y = 4y - 8 ( subtract 4y from both sides )
x - 3y = - 8 → (2)
Substitute x = y + 6 into (2)
y + 6 - 3y = - 8
- 2y + 6 = - 8 ( subtract 6 from both sides )
- 2y = - 14 ( divide both sides by - 2 )
y = 7
Substitute y = 7 into (1)
x = 7 + 6 = 13
The 2 numbers are 7 and 13