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Firlakuza [10]
2 years ago
5

HELP THIS IS 50 points HALF OF MY GRADE!!:(

Mathematics
1 answer:
Rainbow [258]2 years ago
8 0

there are 18 students are represented on the line plot

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The hypotenuse of a right triangle is 10cm long. The longer leg is 2cm longer than the shorter leg. Find the side lengths of the
Crazy boy [7]
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b =  legs of a right-triangle
c = length of hypotenuse

Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 +   S^2+4S+4  = 100 cm^2   [collect terms and isolate]
2S^2+4S =  100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0   means (S+8)=0, S=-8
or                                   (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm

5 0
2 years ago
22. The height of a triangle is 4 centimeters less than the base. Write a function that
torisob [31]

The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

let the base of the triangle be x

Height of the triangle = x - 4

Area of triangle = 1/2 × base × height

Area = 1/2 × x × (x-4)

Area = 1/2 (x² - 4x)

Area = 1/2 x² - 2 x

We can also write it as a function:

y = 1/2 x² - 2 x

Domain = (3 , ∞)

Range = [0, ∞)

Since 3 is not included in the domain, base of the triangle cannot be 3 cm.

Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

Learn more about function here:

brainly.com/question/2456547

#SPJ9

6 0
1 year ago
What combination of transformations is shown below
Inessa05 [86]

Answer:

rotation ,then reflection

7 0
3 years ago
Read 2 more answers
Maria uses 1 1/2 cups of milk for her cereal and
jonny [76]

Answer:

more, she uses 17.5 cups a week

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Slove the simoltanous equation by using substitution or elimination method 5x-3y=1 3x+2y=1<br>​
xxTIMURxx [149]

<u>By substitution method </u>

5x - 3y =1

3x + 2y = 1

_____o____o____

5x - 3y = 1 \\ 5x = 1  +  3y \\ x =  \frac{1 + 3y}{5}

______o____o_____

3x + 2y = 1 \\ 3( \frac{1 + 3y}{5} ) + 2y = 1 \\  \frac{3 + 9y}{5}  + 2y = 1 \\  \frac{3 +9y + 10y}{5}  = 1 \\  \frac{3 + 19y}{5}  = 1 \\ 3 + 19y = (1)(5) \\ 3 + 19y = 5 \\ 19y = 5 - 3 \\ 19y = 2 \\ y =  \frac{2}{19}

______o_____o____

x =  \frac{1 + 3y}{5}  =  \frac{1 + 3 \frac{2}{19} }{5} \\ x =  \frac{1 +  \frac{6}{19} }{5}  =  \frac{ \frac{19 + 6}{19} }{5}   =  \frac{ \frac{25}{19} }{5}  \\ x =  \frac{25}{19}  \div 5 \\ x =  \frac{25}{19}  \times  \frac{1}{5}  \\ x =  \frac{5}{19}

I hope I helped you^_^

7 0
2 years ago
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