I'm willing to help you with both parts
Answer:
Step-by-step explanation:
Sec B
1) 5p⁻³ = 8*5⁻²
p⁻³ = 2³*5⁻²/5
p⁻³ =2³*5⁻³ { 1/a^m = a^-m}
p⁻³ = 5⁻³ /2⁻³ {a^m = 1/a^-m}
p⁻³ = (5/2)⁻³
p= 5/2
2) 4x² = 81
x² = 81/4
x² = 9² /2²
x² =(9/2)²
x = 9/2
3) 9^x/3 =81
9^x/3 = 9^2
Comparing the powers, x/3 = 2
x = 2*3 =6
x = 6
Answer: The answer is (A) ∠T.
Step-by-step explanation: Given that the polygon ABCDE is congruent to the polygon TVSRK. We are to find the corresponding angle of ∠EAB.
In the two polygons, the corresponding vertices are
A ⇒ T
B ⇒ V
C ⇒ S
D ⇒ R
E ⇒ K.
Therefore, ∠EAB, which is ∠A will correspond to ∠T.
Thus, the correct option is (A) ∠T.
Answer:
3.2
Step-by-step explanation:
4 is in the hundredths place. It is less than 5 so you leave the tenths place alone, so you get 3.2.
