Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Step-by-step explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
<u>The 99% confidence intervals are given by</u>

The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays

( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
<u>Final answer</u>:-
<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>
<u>(0.932 ,1.071)</u>
Answer:
n(9n)(8n+8) = 72x^3+72x^2
Answer:
y = -5x - 2
Step-by-step explanation:
equation formula: y = mx + c
m = -5
-12 = -5(2) + c
c = -2
⇒ y = -5x - 2
Answer:(2/3) + (9/10) = 47/30
= 1 17/30
Step-by-step explanation:
Answer:
11.3 ft
Step-by-step explanation:
sin = opp/hyp
hyp = opp/sin
AC = 10/sin62
Use calculator
AC = 11.325700506890392
11.3 ft