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Vladimir [108]
3 years ago
8

Simplify the midpoint of PR. Q (2b, 2c) R (2a+2b, 2c) Pl(0,0) S (2a, 0)

Mathematics
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

The midpoint of PR is;

(a + b, c)

Step-by-step explanation:

Here, we want to get the coordinates of the midpoint of PR

To get these, we make use of the midpoint formula

Mathematically, that will be;

(x,y) = (x1+y1)/2, (x2+y2)/2

(x1,y1) = (0,0)

(x2,y2) = (2a+2b, 2c)

The midpoint is thus;

(2a+2b)/2 , 2c/2

= (a + b, c )

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Larger = 2smaller + 1 ----(1)
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put (2) in (1)
larger = 2(2larger-17) + 1
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3 0
3 years ago
(3) Two people are at an elevator. At the same time one person starts to walk away from the elevator at a rate of 2 ft/sec and t
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Answer:

The rate at which the distance between the two people is changing 15 seconds later is 7.28 ft/sec.

Step-by-step explanation:

Here, we note the following

Let the person walking way fom the elevator be X

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Therefore after 15 seconds, their positions will be;

For X,  2 ft/sec × 15 s = 30 ft away from the elevator

For Y,  7 ft/sec × 15 s = 105 ft up in the elevator

At that instant, the distance between them is given as

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d = √11925 ft²  = 109.202 ft

The rate of change of the distance between the two peopl, X and Y is given as

\frac{dd^2}{dt} = \frac{dx^2}{dt} + \frac{dy^2}{dt}

Therefore,  2d\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt} or d\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}

Since \frac{dx}{dt} is given as 2 ft/sec and \frac{dy}{dt} = 7 ft/sec

Then  d\frac{dd}{dt} = 30 \times 2 + 105 \times 7 = 795\\

\frac{dd}{dt} = \frac{795}{109.202 } =7.28 ft/sec

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