In Mr. Porter's equation the initial "d" represents the initial value of the house. The term "+0.21d" represents the increase in value, 21% of its original value (d).
The correct percentage increase is 21%.
Answer:
31.5 cm
Step-by-step explanation:
scale of an architecture is ratio of size of drawing to size of actual object.
Given size of football field is 160 feet by 360 feet
Given that on map shortest side is 14
since value of shortest side is 160 feet
then
scale defined for this football filed will be
scale = size of shortest side on model/size of shortest side of actual football field
scale = 14/160
Given that scale will remain same for longer side as
14/160= size of longer side on model/size of longer side of actual
14/160 = size of longer side on model/360
thus,
size of longer side on model = (14/160) * 360
size of longer side on model = 14*360/160 = 31.5
Thus, the other side of model that is longer side is 31.5 cm
9514 1404 393
Answer:
(c) dZ/dt = 11/√544, so moving away at about 0.47 m/s
Step-by-step explanation:
The (x, y) coordinates of the car are related by the fact that they are on a circle centered at (12, 7) with a radius of 5. Then their rates of change are related by the derivative of the circle equation with respect to time.
(x -12)^2 + (y -7)^2 = 25
2(x -12)x' +2(y -7)y' = 0
y' = -(x -12)/(y -7)x'
At the time and point of interest, we have ...
y' = -(15 -12)/(11 -7)(1) = -3/4
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The distance (z) to the observer is given by the Pythagorean theorem:
z^2 = (x -0)^2 +(y -2)^2
and its rate of change with time is ...
2z·z' = 2(x-0)x' +2(y -2)y'
The distance d at the point of interest is ...
z = √((15 -0)^2 +(11 -2)^2) = √(225 +81) = √306 = 3√34
So, the rate of change of distance to the observer at the time and point of interest is ...
z' = (x(x') +(y -2)y')/z
z' = ((15)(1) +(11-2)(-3/4))/(3√34) = (33/4)/(3√34)
z' = 11/√544 ≈ 0.47 . . . m/s
The slope is 12x, remember the slope is the number value before the variable!