Answer:
–0.11 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 6.1 g
Initial velocity (u) = 350 m/s
Time (t) = 0.32 mins
Final velocity (v) = 0 m/s
Force (F) =?
Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
0.32 mins = 0.32 × 60 = 19.2 s
Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:
Initial velocity (u) = 350 m/s
Time (t) = 19.2 s
Final velocity (v) = 0 m/s
v = u + at
0 = 350 + (a × 19.2)
0 = 350 + 19.2a
Collect like terms
0 – 350 = 19.2a
–350 = 19.2a
Divide both side by 19.2
a = –350 / 19.2
a = –18.23 m/s²
Next, we shall convert 6.1 g to Kg.
1000 g = 1 Kg
Therefore,
6.1 g = 6.1 g × 1 Kg / 1000 g
6.1 g = 0.0061 Kg
Finally, we shall determine the force. This can be obtained as follow:
Mass (m) = 0.0061 Kg
Acceleration (a) = –18.23 m/s²
Force (F) =?
F = ma
F = 0.0061 × –18.23
F = –0.11 N
NOTE: The negative sign indicates that the force is in opposite direction.
