The basic relationship between voltage, resistance and current of an electrical device is given by Ohm's law:
where
V is the voltage
I is the current
R is the resistance
The hot plate in our problem is connected to a source of V=120 V and it has a resistance of
, therefore we can rearrange the previous equation to calculate the current through the device:
We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.
Firstly, let's calculate the momentum of both objects using p=mv:
Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s
Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s
Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s
Substituting this into p=mv again:
1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!
1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.
In the free body diagram for the 500 N weight, we have a figure Y with the net force equations
• horizontal net force:
∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0
• vertical net force:
∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0
From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have
2 T sin(θ) = 500 N
and if the maximum permissible tension is T = 1800 N, it follows that
sin(θ) = (500 N) / (3600 N) ⇒ θ = arcsin(5/36) ≈ 7.9°
is the smallest angle the rope can make with the horizontal.
Relative time is the physical subdivision of the rocks found in the Earth's geology and the time and order of events they represent. Absolute time is the measurement taken from the same rocks to determine the amount of time that has expired
Explanation:
Question:
A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 and lands at bottom of the stairs. The staircase has a horizontal length of 8.00 m. We can ignore air resistance. What is the skater's vertical displacement during the jump?
Answer:
y = 1.48 m
Explanation:
Projectile motion is a two dimensional motion experienced by an object or particle that is subjected near the Earth's surface and moves along a curved path under the influence of gravity only. The path followed by projectile motion is called projectile path.
As the skateboarder followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.
Also Skateboard jumps horizontally, So initial velocity has only horizontal component.
Horizontal component of initial velocity = 
= 14.5 m/s
Horizontal displacement = x = 8.00 m
Vertical displacement = y = ?
Using the following formula
x = t
8 = (14.5)(t)
t = 0.55 s
As skateboarder jumps horizontally, So there is no vertical component of velocity.
According to 2nd equation of motion
y = 
As 
So
y = 0.5gt²
y = 0.5*9.8*(0.55)²
y = 1.48 m
