The protons will possess a force pointing to the right.
The force is called Laurentz Force, which is measured by: F = qvB
Here, q is positive for proton, v and B are cross product determined by right hand rule.
The rock would be at a point 12 m from water at a time <u>4.8 s</u>.
Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

Use the equation of motion,

The rock falls under the acceleration due to gravity, directed down wards.
Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

Solve the quadratic equation for t.

Taking only the positive value,

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.
Heat rises therefore the heat from the fire rises up to your hand... i didnt have any answer choices to work with sorry
The mode in this case would be 125 because it occurs the most in the sequence of numbers.
Explanation:
Given
initial velocity(v_0)=1.72 m/s

using 
Where v=final velocity (Here v=0)
u=initial velocity(1.72 m/s)
a=acceleration 
s=distance traveled

s=0.214 m
(b)time taken to travel 0.214 m
v=u+at


t=0.249 s
(c)Speed of the block at bottom

Here u=0 as it started coming downward

v=1.72 m/s