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Fudgin [204]
3 years ago
11

A box of granola weighs 115 ounces. How much pounds does the box weight?

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0
7.9 pounds because 115 ounces is 7.9 pounds.hope this helps
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Answer:“ C ”

“month” on the x axis and “log” on the y axis

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Find the value of this expression if x = -2.<br>x^2 – 8/x + 6​
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Answer:

-1

Step-by-step explanation:

x^2 – 8

-----------

x + 6​

Let x = -2

(-2)^2 – 8

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Exponents first

4 – 8

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-2 + 6​

Then complete the numerator and denominator

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Then divide

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How is 8/15 written as a mixed number?​
babymother [125]

Answer:

8/15 is already a proper fraction, therefore it cannot be converted to a mixed number. Hope this helps!

Step-by-step explanation:

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3 years ago
A car is traveling down a highway at a constant speed, described by the equation d=65t, where d represents the distance, in mile
Alexxx [7]

Answer:

Step-by-step explanation:

We are given an equation d = 65 t, where d represents the distance, in miles, that the car travels at this speed in t hours.

We know distance, speed and time relation

d = s * t.

Where  d represents the distance, that the car travels at this speed in t  at the speed s.

If we compare that relation with the given equation, we can see s = 65.

So,

a) The 65 tell us speed of 65 miles per hour in this situation.

b) Second part seems to be incorrect. Please check it again.

c) We are given distance = 26 miles.

Plugging d= 26 in the given equation.

26 = 65 t

Dividing both sides by 65, we get

26/65 = t

t= 0.4 hours.

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6 0
3 years ago
Question Help Suppose that the lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a
koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So \mu = 5656, \sigma = 333.3

(a) What proportion of light bulbs will last more than 6262 ​hours?

The pvalue of the z-score of X = 6262 is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.

Z = \frac{X - \mu}{\sigma}

Z = \frac{6262 - 5656}{333.3}

Z = 1.82

Z = 1.81 has a pvalue of .96562. This means that 96.562% of the light bulbs are going to last less than 6262 hours. So

P = 100% - 96.562% = 3.438% of the light bulbs will last more than 6262 hours.

​(b) What proportion of light bulbs will last 5252 hours or​ less?

This is the pvalue of the zscore of X = 5252

Z = \frac{X - \mu}{\sigma}

Z = \frac{5252- 5656}{333.3}

Z = -1.21

Z = -1.21 has a pvalue of .1131. This means that 11.31% of the light bulbs will last 5252 hours or less.

(c) What proportion of light bulbs will last between 5858 and 6262 ​hours?

This is the pvalue of the zscore of X = 6262 subtracted by the pvalue of the zscore X = 5858

For X = 6262, we have that Z = 1.81 with a pvalue of .96562.

For X = 5858

Z = \frac{X - \mu}{\sigma}

Z = \frac{5858- 5656}{333.3}

Z = 0.61

Z = 0.61 has a pvalue of .72907.

So, the proportion of light bulbs that will last between 5858 and 6262 hours is

P = .96562 - .72907 = .23655

23.655% of the light bulbs are going to last between 5858 and 6262 hours.

​(d) What is the probability that a randomly selected light bulb lasts less than 4646 ​hours?

This is the pvalue of the zscore of X = 4646

Z = \frac{X - \mu}{\sigma}

Z = \frac{4646- 5656}{333.3}

Z = -3.03

Z = -3.03 has a pvalue of .0012. This means that 0.12% of the light bulbs will last 4646 hours or less.

5 0
3 years ago
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