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sertanlavr [38]
3 years ago
13

What is the lcd of (3x)/(x + 3), 3/(x ^ 2 - 9)

Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

Simplify the denominator.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

x

2

−

5

x

+

6

Factor

x

2

−

5

x

+

6

using the AC method.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

(

x

−

3

)

(

x

−

2

)

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

(

x

+

3

)

(

x

−

3

)

,

(

x

−

3

)

(

x

−

2

)

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number

1

is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of

1

,

1

is the result of multiplying all prime factors the greatest number of times they occur in either number.

1

The factor for

x

+

3

is

x

+

3

itself.

(

x

+

3

)

=

x

+

3

(

x

+

3

)

occurs

1

time.

The factor for

x

−

3

is

x

−

3

itself.

(

x

−

3

)

=

x

−

3

(

x

−

3

)

occurs

1

time.

The factor for

x

−

2

is

x

−

2

itself.

(

x

−

2

)

=

x

−

2

(

x

−

2

)

occurs

1

time.

The LCM of

x

+

3

,

x

−

3

,

x

−

3

,

x

−

2

is the result of multiplying all factors the greatest number of times they occur in either term.

(

x

+

3

)

(

x

−

3

)

(

x

−

2

)

Step-by-step explanation:

there does that help

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4 0
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elena-14-01-66 [18.8K]

Answer:

B.

Step-by-step explanation:

First, notice that we can cancel out an x in the second term. Thus:

\frac{3x^2}{x^2+x} =\frac{3x^2}{x(x+1)} =\frac{3x}{x+1}

As with the last question, change the sign to multiplication and "flip" the second term:

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Multiply straight across:

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Cancel the (x+1) term:

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B.

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