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kolbaska11 [484]
3 years ago
14

Equation Editor The coordinates of points A and B are (−7, 5) and (4, −3), respectively. What is the distance, in units, between

the points?
Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

√185 = 13.6

Step-by-step explanation:

Distance² = (x' - x)² + (y' - y)²

Distance² = (-7 - 4)² + (5 - -3)² = (-11)² + (8)² = 121 + 64 = 185

Distance = √185

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The sum of two numbers is 12. The difference of the same two numbers is −4. Find the two numbers.
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Answer:

  4 and 8

Step-by-step explanation:

Let 'a' represent one of the numbers. Then the other is 12-a, and their difference is ...

  a - (12-a) = -4

  2a = 8 . . . . add 12

  a = 4 . . . . . divide by 2

  12-a = 8 . . . . find the other number

The two numbers are 4 and 8.

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Answer:

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3 years ago
Determine the values of the unlabeled parts of the triangle.
____ [38]

Answer:

∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

90 + 26.6 + ∠Q = 180

∠Q + 116.6 = 180

∠Q = 180 - 116

∠Q = 63.4°

We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ  :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47

4 0
3 years ago
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