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3 years ago

What are the coordinates of the point plotted on this graph?

Mathematics

2 answers:

timurjin [86]3 years ago

5 0

C the left bottom corner is negative. The answer is (-1,-8)

laila [671]3 years ago

4 0

The answer is C: (-1, -8)

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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

Does anyone get this question plss

a_sh-v [17]

Answer:

D) 1.0

Step-by-step explanation:

if y = 1 then x = 1

6 0

3 years ago

PLS HELP!!! due to inflation nominal prices are usually there were to demand increases. After the second increase the price for

SashulF [63]

Answer:

The first increase was of 60%.

Step-by-step explanation:

The initial value of the product is x.

The first increase was of y.

The second increase is of 25%, that is, 1.25.

The final price was double the original, so 2x.

This situation can be modeled by the following equation:

$xy(1.25) = 2x$

We want to find y.

Simplifying by x

$1.25y = 2$

$y = \frac{2}{1.25}$

$y = 1.6$

After the first increase, the value was 1.6 of the original value, that is a increase as a percent of (1.6 - 1)*100 = 60%.

8 0

3 years ago

Chantelle is going on an 8 day hike of 82.5 miles. she plans to hike 8.25 hours everyday for each of those 8 days. how many mile

stealth61 [152]

The answer would be 1.25 miles per hour hiked

4 0

3 years ago

You have 10 cups of a cleaning solution that is 10% white vinegar and 90% water. You want the mixture to be 50% white vinegar an

lisabon 2012 [21]

Let
x-->volume of white vinegar you need to add to the mixture (measured in cups)
then
the amount of the pure vinegar in the mixture will be -----> (10*0.1 + x) cups
the volume of liquid will be ---------> 10 + x
the concentration equation is-------> [(10*0.1 + x)/(10+x)]=0.50multiply both sides by (10+x) and then simplify

(10*0.1 + x)=(10+x)*0.50-----------> 1+x=5+0.50x-------> 0.50x=4
x=8

the answer is
you need to add 8 of a cup of the pure vinegar to the mixture

7 0

3 years ago