Answer:
Step-by-step explanation:
D
It would also be 25 degrees
Given:
The height of a golf ball is represented by the equation:
To find:
The maximum height of of Anna's golf ball.
Solution:
We have,
Differentiate with respect to x.
For critical values, 
.
Differentiate y' with respect to x.
Since double derivative is negative, the function is maximum at .
Substitute in the given equation to get the maximum height.
Therefore, the maximum height of of Anna's golf ball is 6.25 units.
Divide 224 by 8 and you will get 28.
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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