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3 years ago

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Yesterday, 92% of the sixth grade students had their MacBooks in class. There are 200 students in 6th grade. How many students d

id not have their MacBooks?

1 answer:

Greeley [361]3 years ago

8 0

Answer:

hdhdjdjrrjrurururjrjrjrjejejeueieurururrur

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Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

<h3>Pair: 8, 15, 17</h3>

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

<h3>Pair: 10, 15, 20</h3>

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 12, 18, 22</h3>

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 7, 9, 11</h3>

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago

When 5√20 is written in simplest radical form , the result is k√5 what is the value of K

Vladimir [108]

Answer:

Step-by-step explanation:

√20 can be rewritten as the product of two radicals: √4√5,

and √4 = 2.

Thus, 5√20 = 5(2)√5 = 10√5. Thus, B: 10 is correct; k = 10.

7 0

3 years ago

A regular polygon is drawn in a circle so that each vertex is on the circle and is connected to the center by a radius. Each of

AlexFokin [52]

Answer:

EACH central angle = 360 / number of sides

number of sides = 360 / each central angle

number of sides = 360 / 40

number of sides = 9

5 0

3 years ago

Solve for w: 30= 6/5w

Inga [223]

Answer:

w = 25

(Hope this helps! Btw, I am the first to answer.)

7 0

3 years ago

Read 2 more answers

Could you describe the expression 2(3+4) as a product of two factors?

natta225 [31]

the answer will be 10 just multiply the numbers

6 0

2 years ago