Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
It is always because if you have an improper fraction, the larger number is always the numerator. To get a reciprocal, you flip the fraction so that the denominator is the numerator, and vice versa. If the numerator is always bigger, and you make it the denominator, it would be proper.
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Answer:
1.0
Step-by-step explanation:
If you have any questions feel free to ask in the comments
One pair of opposite sides both parallel and congruent implies a parallelogram.
