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ipn [44]
2 years ago
12

Someone please please help me!

Mathematics
1 answer:
Korvikt [17]2 years ago
3 0

Answer:

B os correct because its multiplied itself 5 times

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The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer
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Answer:

The outer circle is 16 feet larger than the inner circle (68 - 52).

Step-by-step explanation:

Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).

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