Well, let's take a peek at the graph of that line, hmmm let's pick two points, heck, those tow on the extremes anyway, and those are (-5,2) and (5,-1), alrite.. now, let's do some checking on that.

I can’t see anything on the screen
Solution is on the picture.
Answer:
The required formula is:
Step-by-step explanation:
The total number of squares of the the first term = 4
The total number of squares of the the second term = 7
The total number of squares of the the third term = 10
so,



Finding the common difference d


As the common difference 'd' is same, it means the sequence is in arithmetic.
So
If the initial term of an arithmetic progression is
and the common difference of successive members is d, then the nth term of the sequence
is given by:

Therefore, the required formula is:
That’s not the full question but if it was it would be greater bc 10 - 10=0 but 10-10+15 would equal 15 instead of 10