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tiny-mole [99]
3 years ago
7

What is the reason for each step in the solution of the equation 12-5x+6x=4

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer: x=-8

Step-by-step explanation: 12-5x+6x=4                                                                 1. Combine like terms: -5x+6x+12=4                                                                       2. Simplify: x+12-12=4-12                                                                                         3. Subtract 4 from -12 so that you can find out what x is: x=-8

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the width of a rectangle is 3 units less than the length. if the area is 130 square units, then find the dimensions of the recta
Basile [38]

Answer:

Length = 10

Width = 13

Step-by-step explanation:

If the width of a rectangle is 3 units less than the length and if the area is 130 square units, the length is 10 units and the width is 13 units.

Formula: A=wl

Therefore, you have to find what two numbers multiply together in order to recieve 130 units.

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4 years ago
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-10/5+2(7-9)^2
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Answer: -4

Reasoning: so first you need to subtract the 7 from the 9 to get -2. Then you square it to get 4 because a negative 2 times -2 is 4. Then you multiply the 4 by the 2 to get 8. You can simplify the -10/5 to -1/2 and multiply that by the 8 to get -8/2 which simplified out to -4.


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Simplify to create an equivalent expression <br> −5(3p+3)+9(−7+p)
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Step-by-step explanation:

-5 (3p + 3) + 9(-7 + p)

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Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
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Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

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