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Solnce55 [7]
3 years ago
6

Х

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

225 boards

Step-by-step explanation:

99 ft/0.44 ft = 225 ft

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Solve this problem please
djyliett [7]

The formula for depreciation is:

y=x(1-r)^t

Where x = Initial value,

y= Amount after depreciation.

r= Rate of depreciation,

t = time (in years)

According to given problem,

x = 1040, y= 944 and t = 12 months =1 year.

So, first step is to plug in these values in the above formula, So,

944 = 1040(1-r)^1

944 = 1040 (1 -r)

\frac{944}{1040} =1-r Divide each sides by 1040.

0.907692308 =1 - r

0.907692308 - 1 = -r Subtract 1 from each sides.

-0.092307692 = -r

So, r = 0.09 or 9%.

Now plug in 0.09 in the above equation to get the depreciation equation. So,

y = x (1- 0.09)^t

So, y = 0.91x^t

b) To find the value of the bike after 5 months,

plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.

So, y= 1040 *(0.91)^{0.41667}

y = 1040 * 0.961465659

y = 999.9242852

y = 1000 (Rounded to nearest integer).

Hence, the value of the bike after 5 months is $1000.

7 0
3 years ago
Simplify. 32 + 16 + 8 A) 4 + 6 2 B) 6 + 4 2 C) 10 + 2 D) 10 2
Ann [662]

Answer:

its 56 if you simplify 32 + 16 + 8

6 0
3 years ago
(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

t=1min Sugar=0.27 Kg

Step-by-step explanation:

Data

Tank = 2640 L (pure water)

Sol=0.09kg Sugar per liter

Vin = Vout = 3L/min

Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

\frac{3L}{min}*\frac{0.09Kg}{L}=0.27kg/min

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME with an explanation. Thanks in advance
REY [17]

Answer:

3) 0.30

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given  'A' plays a sport

          B work part time

Given P(A) = 0.48

         P(B)  = 0.40

        P(A∩B) =0.12

       P(A∪B)¹ =0.24

<u><em>Step(ii)</em></u>:-

By using conditional probability

P(B/A) = \frac{P(BnA}{P(A)}

and similarly P(A/B) = \frac{P(AnB}{P(B)}

The probability a randomly selected<em> student plays a sport</em> given they work part time

Now P(A/B) = \frac{P(AnB}{P(B)}

       P(A/B) = \frac{0.12}{0.40}= 0.30

<u>Final answer</u>:-

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

8 0
3 years ago
What is 2,767,545 rounded to the nearest tenth?
solmaris [256]

2,767,550 is the answer

5 0
3 years ago
Read 2 more answers
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