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2 years ago

Find the value of x , then find the measure of angle A ( show your work ).

Mathematics

1 answer:

sasho [114]2 years ago

7 0

140 = (2x - 6) + (8x + 4)

140 = 10x - 2

142 = 10x

X = 14.2

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A toy company currently produces 950 toys per day. The company plans to increase the number of toys produced per day by 55 each

kherson [118]

Answer:

1335 toys per day.

Step-by-step explanation:

The number of toys produced per day can be modeled by the following function:

$N(t) = N(0) + at$

In which N(0) is the current number and a is the increase.

A toy company currently produces 950 toys per day. The company plans to increase the number of toys produced per day by 55 each year.

This means that $N(0) = 950, a = 55$

$N(t) = N(0) + at$

$N(t) = 950 + 55t$

If the company follows through on this plan, how many toys will it be producing per day in 7 years?

This is N(7).

$N(t) = 950 + 55t$

$N(7) = 950 + 55*7 = 1335$

1335 toys per day.

8 0

3 years ago

Help asap geometry 1 honors!!!!

Elis [28]

Answer: 12

Step-by-step explanation:

6 0

3 years ago

Which graph below shows the object above rotated around the point (4,4)?

faltersainse [42]

Answer:

A. IV

Step-by-step explanation:

The figure is congruent, but rotated. Additionally, the figure is rotated/on point (4,4).

7 0

3 years ago

Lisa purchased a hat for $10, a purse for $20, and a book for $23. The sales tax rate was 7.2 percent. What was the total amount

shusha [124]

10+ 20+ 23 = 53
53 x 0.072 = 3.816
53 + 3.82 =
$56.82

4 0

3 years ago

Read 2 more answers

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago