Question

I'm new to this and I dont really understand this

Answer 1

Answer:

So starting off with 1a f(4)

We simply substitute x with 4 for the function

f(4)=2(4)-5

f(4)=8-5

f(4)=3

Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).

gf(4), basically means functions g and f are being multiplied and their variables are being substituted with 4.

g(4)=4^2+3

g(4)=16+3

g(4)=19

and we also know from before that f(4)=3, so we'll do 19 times 3 which is 57

For the next two, I may be wrong, but I'm still going to try:

anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2

And then for g^-1, we'll have 1/g(x)=$\sqrt{x-3} \sqrt{x-3}$

Hope I helped :)