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3 years ago

If tan e = 1.3, what is the value of cot (90° - 9)?

Mathematics

1 answer:

ella [17]3 years ago

7 0

Answer:

Step-by-step explanation:

We are given that:

$\tan(\theta)=1.3$

And we want to find:

$\cot(90^\circ -\theta)$

Remember that tangent and cotangent are co-functions. In other words, they follow the cofunction identities:

$\tan(\theta)=\cot(90^\circ-\theta)\text{ and } \cot(90^\circ-\theta)=\tan(\theta)$

Therefore, since tan(θ) = 1.3 and cot(90° - θ) = tan(θ), then cot(90° - θ) must also be 1.3.

Our answer is A.

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SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

Sloan [31]

ANSWER

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

EXPLANATION

The given polynomials are:

$G = - 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4}$

and

$P = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4}$

We want to subtract these two polynomials.

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} - (- 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4} )$

Expand the right hand side to obtain:

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} + 3 {w}^{4} - 2 {w}^{2} {z}^{2} - 5z^{4}$

Group the similar terms:

$P-G = 8 {w}^{4} + 3 {w}^{4}- 3{w}^{2} {z}^{2} - 2 {w}^{2} {z}^{2} - 5z^{4} + z^{4}$

Combine the similar terms to get:

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

7 0

3 years ago

When n is small (less than 30), how does the shape of the t distribution compare to the normal distribution?

Anna [14]

When n is small (less than 30), how does the shape of the t distribution compare to the normal distribution then"it is flatter and wider than the normal distribution."

<h3>What is normal distribution?</h3>

The normal distribution explains a symmetrical plot of data around the mean value, with the standard deviation defining the width of the curve. It is represented graphically as "bell curve."

Some key features regarding the normal distribution are-

The normal distribution is officially known as the Gaussian distribution, but the term "normal" was coined after scientific publications in the nineteenth century demonstrated that many natural events emerged to "deviate normally" from the mean.
The naturalist Sir Francis Galton popularized the concept of "normal variability" as the "normal curve" in his 1889 work, Natural Inheritance.
Even though the normal distribution is a crucial statistical concept, the applications in finance are limited because financial phenomena, such as expected stock-market returns, do not fit neatly within a normal distribution.
In fact, prices generally follow a right-skewed log-normal distribution with fatter tails.

As a result, relying as well heavily on the a bell curve when forecasting these events can yield unreliable results.

To know more about the normal distribution, here

brainly.com/question/23418254

#SPJ4

6 0

1 year ago

Choose all the numbers that are common multiples of 12 and four

irina [24]

Answer:

12, 24 , and 36

Step-by-step explanation:

6 0

3 years ago

A bag contains 25 marbles;10 black,13 red,and 2 blue. A marble is drawn from the bag at random.

Deffense [45]

For the answer to the question above asking to e<span>xplain why the events "getting a black marble" and "getting a red marble" are mutually exclusive.
</span>A marble can have only one color, so you cannot choose a marble that is both black and red. Therefore the events are mutually exclusive (cannot happen simultaneously)

3 0

3 years ago

The expanded fom of (a-b)²

emmainna [20.7K]

Answer:

Step-by-step explanation:

$(a-b)^{2}$ = $a^{2}$ - 2ab + $b^{2}$