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OLEGan [10]
3 years ago
6

Evaluate the formula v=bh/3 for B = 15 in.2 and h = 28 in.

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0
I think its v=5.28. I hope this helps
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How would I simplify the equation 5u^6x^2+20wx/15x^4
Akimi4 [234]

Answer:

The simplified form is 5u^6x^2+\frac{4w x^{-3}}{3}

Step-by-step explanation:

To simplify the expression given to use, we need to reduce the given expression in its simplest form. There should not be any possibility for the further cancelling out of the division terms, if any.

Now the expression that is given to us is:

5u^6x^2+\frac{20wx}{15x^4}\\

Here we will simplify it, as follows:

5u^6x^2+\frac{20wx}{15x^4}\\=5u^6x^2+\frac{4w}{3x^3}\\=5u^6x^2+\frac{4w x^{-3}}{3}

So this is the required simplified form.

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Step-by-step explanation:

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Divide 2/8 by 9/18 . Input your answer as a reduced fraction.\
Katen [24]

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{2}{8}\div\frac{9}{18}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Simplify \ \frac{2}{8} \ to \ \frac{1}{4}. \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\div\frac{18}{9}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: a\div \frac{b}{c}=a\times \frac{c}{b}a \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\times\frac{18}{9}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: \frac{a}{b} \times \frac{c}d{}=\frac{ac}{bd}. \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1\times18}{4\times9} \ \to \ \ Multiply  }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{ \frac{18}{36}= }}\boxed{\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{2}  }} \end{gathered}$}} \end{gathered}$}

8 0
2 years ago
Read 2 more answers
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