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Vika [28.1K]
3 years ago
8

Center at (0, 0), radius 2

Mathematics
1 answer:
Step2247 [10]3 years ago
6 0

Answer:

x² + y² = 4

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius]Here r = 2, thus

x² + y² = 4

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. Find the inverse of the function below on the given interval and write it in the form yequalsf Superscript negative 1 Baseline
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Answer:

The inverse of the function is f^{-1}(x)=\frac{x-5}{3}.

Step-by-step explanation:

The function provided is:

f (x)=3x+5

Let f(x)=y.

Then the value of <em>x</em> is:

y=3x+5\\\\3x=y-5\\\\x=\frac{y-5}{3}

For the inverse of the function, x\rightarrow y.

⇒ f^{-1}(x)=\frac{x-5}{3}

Compute the value of f[f^{-1}(x)] as follows:

f[f^{-1}(x)]=f[\frac{x-5}{3}]

               =3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x

Hence proved that f[f^{-1}(x)]=x.

Compute the value of f^{-1}[f(x)] as follows:

f^{-1}[f(x)]=f^{-1}[3x+5]

               =\frac{(3x+5)-5}{3}\\\\=\frac{3x+5-5}{3}\\\\=x

Hence proved that f^{-1}[f(x)]=x.

8 0
3 years ago
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