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HACTEHA [7]
2 years ago
9

Lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles without replacing them.

Mathematics
1 answer:
QveST [7]2 years ago
6 0

Answer:

It's the second option, 0.13.

Step-by-step explanation:

Step 1 : Find how many marbles there are in the bag all together.

4 + 4 + 12 = 20 marbles all together

Step 2 : Find what the probability of choosing a red marble is first.

4 red marbles out of 20 marbles =

P_{1} = \frac{4}{20}

Step 3 : Find the probability of choosing a yellow marble now.

Since one red marble was already taken, there are less marbles in total.

Instead of 20 marbles now there are only 19 marbles.

There are 12 yellow marbles out of 19 marbles =

P_{2} = \frac{12}{19}

Step 4 : To get the probability of both of these events happening, we multiply the 2 probabilities.

\frac{4}{20} · \frac{12}{19} = \frac{12}{95}

Step 5 : Express your answer as a decimal.

12 ÷ 95 = 0.12631578947

Rounded to the nearest hundreth that's 0.13.

It's the second option, 0.13.

Hope this helps, please mark brainliest if possible. Have a nice day. :)

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Verizon [17]

Answer:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

s_1 = 3.4 sample standard deviation for group 1

s_2 = 3.5 sample standard deviation for group 2

n_1 = 200 sample size group 1

n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df= n_1 +n_2 -2= 200+200-2= 398

The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

5 0
3 years ago
Can you please help me thanks
mash [69]

Answer:

x = 9.6

Step-by-step explanation:

Before we can figure out what x is, we need to figure out what the unlabeled side is. To figure that out, multiply the hypotenuse (12) by the sine of the angle labeled (34)

12 * sin(34)

<em>sin(34) equals 0.559192903470747; I'll round it to 0.6 for convenience.</em>

12 * 0.6

<em>Now simply multiply 12 by 0.6 to get 7.2.</em>

The unlabeled side is approx. 7.2 units long.

Now we know what the unlabeled side is. Now, to find x, find the square root of 12 squared minus 7.2 squared.

x = √12² - 7.2²

<em>12 squared is 144; 7.2 squared is 51.84.</em>

x = √144 - 51.84

<em>Subtract 51.84 from 144 to get 92.16.</em>

x = √92.16

<em>The square root of 92.16 is 9.6 (on the spot!).</em>

x equals 9.6.

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2 years ago
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No, I think you just round it to $65
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If i have 4 pounds of beef and it costs $9.56 how much would it cost me if I had 1 pound of beef
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to do this just divide 9.56 by 4 to get $2.39

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It would be 1/7 chance cause there are 7 people total but you have the 1 chance that you are going to get your own name
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