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fomenos
3 years ago
14

A wooden roller coaster contains a run in the shape of a sinusoidal​ curve, with a series of hills. The crest of each hill is 10

8 feet above the ground. If it takes a car 1.9 seconds to go from the top of a hill to the bottom ​(4 feet off the​ ground), find a sinusoidal function of the form y = A sin(ωt - Φ) + B that models the motion of the coaster train during this run starting at the top of a hill.
Mathematics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

y(t)=52sin(3.3t+\pi/2)+56

Step-by-step explanation:

We are given that

Height of crest, h=108 feet

Time for one cycle, T=1.9 s

We have to find a sinusoidal function of the form y = A sin(ωt - Φ) + B that models the motion of the coaster train during this run starting at the top of a hill.

We are given

y=Asin(\omega t-\phi)+B

Amplitude,A=\frac{108-4}{2}=52 feet

B=A+4=52+4=56 feet

\omega=\frac{2\pi}{T}

Using the formula

\omega=\frac{2\pi}{1.9}=3.3/s

We assume,

Horizontal shift \phi=-\frac{\pi}{2}

Substitute the values

y(t)=52sin(3.3t+\pi/2)+56

Hence, the  sinusoidal function  that models the motion of the coaster train during this run starting at the top of a hill is given by

y(t)=52sin(3.3t+\pi/2)+56

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Answer:

3

Step-by-step explanation:

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4 0
3 years ago
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2m3 of soil containing 28% silt was mixed into 1 m3 of soil containing 13% of silt. What is the silt content mixture?
Leto [7]
Alright
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answer is D
6 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
A water well is to be drilled in the desert where the soil is either​ rock, clay or sand. The probability of rock ​P(R)equals=0.
GaryK [48]
The tree diagram for the probability is shown below

P(Clay|Positive) is read 'Probability of Clay given the result is Positive'.

This is a case of conditional probability.

The formula for conditional probability is given as
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Hence,
P(Clay|Positive) = 0.1008÷0.5767 = 0.175 (rounded to 3 decimal place)

5 0
3 years ago
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