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earnstyle [38]
3 years ago
6

Find the slope of the line passing through the point (-3, 6) and the origin. M=

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0
You know b=0 because it is passing through the orgin (0,0) and b is the y intercept. You input (-3,6) as (x,y)

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Is the figure an example of parallel lines?
evablogger [386]
Parallel lines are a pair of lines that do not intersect

Therefore this is not an example of parallel lines because the lines intersect

The answer is C
5 0
2 years ago
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A circle has a diameter of 22 cm. What is its circumference?
charle [14.2K]

Answer:

\boxed {\tt 69.08 \ centimeters}

Step-by-step explanation:

The circumference of a circle can be found using the following formula:

c= \pi d

where d is the diameter. We know the diameter of the circle is 22 centimeters. Substitute the value in for d.

d= 22 \ cm

c= \pi* 22 \ cm

We also know we are using 3.14 for pi. Substitute it in for pi.

c= 3.14 * 22 \ cm

Multiply.

c=69.08 \ cm

The circumference of the circle is 69.08 centimeters.

8 0
3 years ago
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A ball is thrown up into the air from a building modeled by the equation:
Arlecino [84]

Answer:

After two seconds

h(2) = -16(2^2) + 115(2) + 19

h(2) = -64 + 115(2) +19

h(2) = 185

Let me know if this helps!

3 0
2 years ago
Which best describes the relationship between the successive terms in the sequence shown? 9, –1, –11, –21, … The common differen
storchak [24]
The difference is -10 because

9-10= 1
-1-10= -11
-11-10= -21

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hope this helps!
5 0
3 years ago
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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

\sqrt{36} =6

BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0
3 years ago
Read 2 more answers
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