<h3>
Answer: D. x = 4</h3>
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Explanation:
First compute f(2)
f(x) = 3x-1
f(2) = 3(2) - 1 ... replace every x with 2; use PEMDAS to simplify
f(2) = 6 - 1
f(2) = 5
When we say g(x) = f(2), we really mean g(x) = 5
g(x) = 2x-3
2x-3 = g(x)
2x-3 = 5 .... plug in g(x) = 5
2x-3+3 = 5+3 ... add 3 to both sides
2x = 8
2x/2 = 8/2 ... dividing both sides by 2
x = 4
<span>No. Its x=4. You couldn't cut the box to much lower without it being absurd.
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</span>
Answer:
Step-by-step explanation:
13/10 = 1.3
14/10 = 1.4
an irrational number between them could be :
1.357 with a bar over the 57.....that bar indicates that the 57 is repeating over and over....there is no end to this number, therefore, it is irrational.
Answer:
No
Step-by-step explanation:
If A were reversible, then such y coudnt not exist, because A⁻¹y would be a solution of the equation Ax=y. This means that A in not reversible, thus, there exist a non zero vector w in R³ such that A*w = 0. If x' were a solution of Ax =z, then x'' = x'+w is a different solution of the equation: Ax'' = A(x'+w) = Ax'+Aw = z+0 = z. This means that a vector z such that there exist a unique solution for the equation Ax=z cant exist.