3 years ago

Question 2

Mathematics

1 answer:

dolphi86 [110]3 years ago

8 0

Answer:

answer J

Step-by-step explanation:

srry if im wrong hope it helps:)

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Solve the equation x^2-4x+85=0

lara [203]

Can't factor
use quadratic
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
1x^2-4x+85=0
a=1
b=-4
c=85

x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-340} }{2}$
x= $\frac{4+/- \sqrt{-324} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}$
remember that √-1=i
x= $\frac{4+/- i(\sqrt{324}) }{2}$
x= $\frac{4+/- i(18) }{2}$
x=2+/-9i

x=2+9i or x=2-9i

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3 years ago

A video game company surveys a random sample of 225 of its best customer and finds that the average gamer spends $406 a year on

Burka [1]

The second survey is more believable because there is randomness in the second rather than the first survey. Since the second company surveyed in all interest levels while the first company only surveyed their best customers. Random sampling like what the second company did helps produce representative samples by removing voluntary response bias and undercover age bias.

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NISA [10]

Answer:

Step-by-step explanation:

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Read 2 more answers

What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10

SashulF [63]

To solve we need to use Pythagoras theorem ( $a^{2} + b^{2} = c^{2}$ )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = $x^{2}$
100+441= $x^{2}$
$\sqrt{541} = \sqrt{ x^{2} }$
23.3≈x

Shorter leg:
$10^2 + x^2=21^2$
$x^2= 21^2-10^2$
$x^{2}$ = 441-100
$\sqrt{ x^{2} } = \sqrt{341}$
x≈18.47

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3 years ago